__engineer a power system for heavy__

__cycle-trucks__
Heavy
utility cycles will become very popular as people wake up to the
reality of climate change. It is not easy to understand how to
provide enough low-speed thrust that is needed to climb steep hills
at legal speeds. Bigger motors are not the best solution. Proper gear
to power matching is much more efficient and economical in terms of
mileage.

- Measure the average steepness of the worst hill that you cannot avoid climbing. Use a level and a ruler (metric or decimal), then divide rise into the span to get the grade percentage.
, plan for at least 400-500lbs (181-226 kg). If you have a cycle-truck or a velomobile that can hold two people, think about at least 600-800lbs (272-362 kg).__Total combined weight__

a.)
Find a power calculator or find a graph for your motor, like the
bicycle speed calculator at kreuzotter.de that has a setting for
Velomobiles. http://www.kreuzotter.de/english/espeed.htm

b.)
Then a gear ratio calculator, like
the
motor
and gear ratio calculator at Electric Scooter Parts Support Center.

c.)
Take
the RPM speed that your motor will produce at the wattage you will
need

*(see a performance graph of the motor)*. Calculate a gear reduction ratio you will need to reduce the speed of the motor to get the maximum thrust. Subtract a little speed (1-2 mph or 1.6-3.2 kph) for the lack of accuracy.
Find
the peak efficiency R.P.M.s and wattage on the label. When a motor is
pushed past the peak efficiency limits too long, it can overheat.
Brushless motors can produce about twice the power on their label for
a few minutes without overheating too much; to get past the steepest
part of the hill.

the myth of ebike wattage:

How much power

**do**you need for a hill? You can work out approximately how much power you need for a hill :

Watts = (total) weight (kg) x 9.81 x speed (M/sec) x gradient (%/100)

For instance 100kg at 20kmh at 4% (3% hill + 1% w+r) = 100 x 9.81 x 20000 x 0.04/3600 = 218 Watts and

100kg at 28kmh at 5.5% (3.5% hill + 2% w+r) = 420 Watts

That is approximately what you can expect from 250w (200w) and 500w (400w) motors.

Many people confuse torque with power. They are different terms. Motors can have high torque and low speed, or low torque and high speed and yet have similar power output. For instance the two different types of e-bike hub motors, the ungeared and internally geared motors have quite similar power, although the former is a high torque low speed motor and the latter is a low torque high speed motor. Its internal reduction gears reduce the speed of the axle and increase torque in same proportion so that the output of the two is quite similar.

Torque is the

**force**that “wants” to turn the motor. Power is the

**rate**at which

**work**is done. The conversion between power and torque is :

Power (watts) = Torque (NewtonMetres) x Rotation
speed (radians/second)

(Newtons are force : 1 kilogram

**weight**= 9.81 Newtons)
In reverse you can work out the motor torque
required to go up a hill at a given speed and wheel diameter and power output

Torque (NewtonMetres)= Watts/radians per second = Watts x 0.5 x diameter)/(kmh/3.6)

218 watts at 20 kmh on 20″ wheel requires
218×3.6×0.254/20=10 NM torque

420 watts at 28 kmh on 26″ wheel requires
420×3.6×0.330/28=17.8 NM torque

You may have seen a Tour de France cyclist going up a 14% slope at about 30kmh. That cyclist is putting out about 1300 watts! You won’t do as well with any bicycle motor. (But if you do have 500 watt motor and do overtake a cyclist training on a hill be considerate – he or she is working hard, but you are not).

Just as with a car’s motor in any gear there is a speed range where the motor performs most efficiently, while at much lower or higher speeds the motor will either struggle or max out. Electric motors have various performances, just as fueled motors do. An electric bike motor can struggle, or stall, just as car motor in the wrong gear will.

You may find a “performance curve” for an electric motor. Usually there will be several variables (power in, power out, rpm or torque, efficiency, current, voltage) plotted against motor rpm or torque. Efficiency will generally be a maximum in the middle range of motor speeds, and be very low at low speeds. The power out will flatten off and not increase much with increasing motor speed despite the input power increasing. This is because the motor loses efficiency at faster speeds and increasing input power has less effect.

For going up steep hills a motor that has high torque at low speed is better. If the speed going uphill is within the high efficiency range the motor will stable and the bike will go up the hill steadily. The speed going uphill will usually be less than the motor’s most efficient speed. In this case the motor will slow, lose efficiency, and struggle…but if you make

**enough**assistance

**to**the motor you can go up any hill at a steady speed.

Wheel speed calculation:

52 sprockets / 12 sprockets on the rear= 4.333 ratio? X 60rpm crank speed x (20” x pi=62.8inch circumference) = 16327.987 inch min. / 12 inch = 1360.6655ft/min. x 5280ft x 60min/hr= 15.45 mi/hr

Gear reduction: Calculate wheel speed needed then find ratio of gears:

Wheel diameter x pi x motors peak efficiency RPM ÷ 12”per foot x 60min. ÷ 5280ft per mile = wheel speed without gear reduction ÷ 15mph = ? to 1( gear reduction needed.)

Low voltage = low speed = high torque. However a huge gear reduction could have advantages, like a smaller motor:

How to make sprockets

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